log[2](3x-5)=16

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Solution for log[2](3x-5)=16 equation:


Simplifying
log[2](3x + -5) = 16

Reorder the terms:
glo * 2(-5 + 3x) = 16

Reorder the terms for easier multiplication:
2glo(-5 + 3x) = 16
(-5 * 2glo + 3x * 2glo) = 16
(-10glo + 6glox) = 16

Solving
-10glo + 6glox = 16

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-16 + -10glo + 6glox = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + -10glo + 6glox = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-8 + -5glo + 3glox) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-8 + -5glo + 3glox)' equal to zero and attempt to solve: Simplifying -8 + -5glo + 3glox = 0 Solving -8 + -5glo + 3glox = 0 Move all terms containing g to the left, all other terms to the right. Add '8' to each side of the equation. -8 + -5glo + 8 + 3glox = 0 + 8 Reorder the terms: -8 + 8 + -5glo + 3glox = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -5glo + 3glox = 0 + 8 -5glo + 3glox = 0 + 8 Combine like terms: 0 + 8 = 8 -5glo + 3glox = 8 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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